How to calculate the FDV of $omni?

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0xTodd
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1 year ago

How to calculate the FDV of $omni?

First of all, the conclusion: the total FDV is $140 million when all chains are combined.

--------Calculation process--------

First, although it is available on 7 chains, the main chain is still ETH.

Secondly, there are 42 trillion $omni on ETH (see Figure 1), but:

→ The first address: the black hole address, destroyed 41.9 trillion $omni;

→ The second address: the cross-chain bridge contract, from my observation, is most likely the Layer0 bridge contract;

Refer to Figure 2, to BSC, BASE, ARB, OP, Polygon, and Canto, they should all go through here.

This matches the 57 billion $omni minted on Arb and other chains in the first transaction.

PS: All other chains have 57 billion, only Canto stands out with 120 billion transferred, making Canto theoretically the best place for $omni liquidity. No wonder Canto, the son of meme, stands out.

PS2: I see the Layer0 contract constantly cross-chain, there is reason to speculate that the official team is also moving assets. The front end is not open, but the back end is moving. I can hear the sound of the abacus even from ten thousand kilometers away.

This also explains why there were initially 57 billion $omni on L2, but the current total supply is less than this number, because the back-end cross-chain has been opened.

→ The third address: Sol bridge contract, just by the name, you can tell it's the bridge contract address for Wormhole, specifically for cross-chain ETH→SOL, with a quantity of 10.5 billion $omni, which matches perfectly.

PS3: Criticizing, Layer0 has raised so much money, and makes the slaves interact every day, but still can't develop a bridge from ETH to Sol, and let the Wormhole, which has been stolen multiple times, monopolize the Sol bridge…

Therefore, the total supply of $omni across all chains = ETH total supply - black hole address = 45.8 billion $omni.

Based on the current price of $0.0032, the FDV is approximately $146 million.

Proof completed, over

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